Refining the conditioning algebra of mutual conditional independence #
A family of σ-algebras that is mutually conditionally independent given m' remains mutually
conditionally independent given any larger algebra m₂ ≥ m' that is itself conditionally
independent of the family's join given m'.
This is the "useless extra information" principle: enlarging the conditioning from m' to m₂
cannot destroy independence when everything m₂ adds is itself conditionally independent of the
family.
The engine, kept private #
The proof rests on a projection identity: if m₁ and m₂ are conditionally independent given
m' ≤ m₂, then for every m₁-set E,
μ⟦E | m₂⟧ =ᵐ[μ] μ⟦E | m'⟧.
The candidate μ⟦E | m'⟧ is m'-strongly measurable, hence m₂-strongly measurable because the
containment m' ≤ m₂ is raw; and its set integral over an m₂-set F is computed by the
pull-out property of conditional expectation together with the product identity of conditional
independence: both ∫ x in F, μ⟦E | m'⟧ x and ∫ x in F, 1_E x equal
∫ x, (μ⟦E | m'⟧ * μ⟦F | m'⟧) x. Uniqueness of the conditional expectation at m₂ finishes.
The identity is deliberately private: its natural generality — integrable functions rather than indicators, one-sided measurability hypotheses — is not yet pinned down by a second consumer, and the σ-algebra-level refinement theorem is the only interface currently consumed.
Contents #
ProbabilityTheory.iCondIndep_of_condIndep_iSup— the refinement theorem.
The StandardBorelSpace hypothesis is inherited from Mathlib's definition of CondIndep and
iCondIndep through condExpKernel; the underlying argument does not use it.
Refining the conditioning of mutual conditional independence. If the family m is
mutually conditionally independent given m', and the larger algebra m₂ ≥ m' is conditionally
independent of the join ⨆ i, m i given m', then the family is mutually conditionally
independent given m₂.
The single hypothesis hci covers both uses of the projection identity — the accumulated finite
intersection and each individual factor are all events of the join.